問題描述

問題解答

當然咯，因為你并發(fā)量是5，但是你的queue中并沒有fork callback，所以并發(fā)量是5，沒有結(jié)束也不會調(diào)新的咯。

var async = require(’async’);var q = async.queue(function(data, callback) { console.log(data.name);// fork callback callback();}, 5);for(var i = 0; i < 10; ++i) { q.push({ name: 0 })}回答2：

var q = async.queue(function (data, callback) { console.log(data.name); callback(null)},5)

少了callback

An asynchronous function for processing a queued task, which must call its callback(err) argument when finished, with an optional error as an argument. If you want to handle errors from an inpidual task, pass a callback to q.push(). Invoked with (task, callback).