java如何消除太多的if else判斷示例代碼
1.簡介
if判斷語句是很多編程語言的重要組成部分。但是,若我們最終編寫了大量嵌套的if語句,這將使得我們的代碼更加復雜和難以維護。
讓我們看看能否使用別的方式來做呢。
設計模式是為了更好的代碼重用性,可讀性,可靠性,可維護性,它有六大原則:
單一職責原則(Single Responsibility Principle,簡稱SRP):該原則是針對類來說的,即一個類應該只負責一項職責. 開放--封閉原則(The Open-Closed Principle簡稱OCP):是說軟件實體(類、模塊、函數等等)應該可以擴展,但是不可以修改。 依賴倒轉原則(Dependence Inversion Principle :針對接口編程,不要對實現編程 里氏代換原則(Liskov Substitution Principle,簡稱LSP):里氏代換原則,子類型必須能夠替換掉他們的父類型 迪米特法則(Law of Demeter):如果兩個類不必彼此直接通信,那么這兩個類就不應當發生直接的相互作用 合成/聚合復用原則(Composition/Aggregation Principle],簡稱CARP):盡量使用合成/聚合,盡量不使用類繼承。合成聚合是“has a”的關系,而繼承是“is a”的關系。2.示例if..else
public int calculate(int a, int b, String operator) { int result = Integer.MIN_VALUE; if ('add'.equals(operator)) { result = a + b; } else if ('multiply'.equals(operator)) { result = a * b; } else if ('divide'.equals(operator)) { result = a / b; } else if ('subtract'.equals(operator)) { result = a - b; } else if ('modulo'.equals(operator)) { result = a % b; } return result;}
switch-case
public int calculateUsingSwitch(int a, int b, String operator) { int result = 0; switch (operator) { case 'add': result = a + b; break; case 'multiply': result = a * b; break; case 'divide': result = a / b; break; case 'subtract': result = a - b; break; case 'modulo': result = a % b; break; default: result = Integer.MIN_VALUE; } return result;}
3.重構
3.1 工廠方式重構
抽象層Operation.java
public interface Operation { int apply(int a, int b);}
加法實現Addition.java:
public class Addition implements Operation { @Override public int apply(int a, int b) { return a + b; }}
減法實現Subtraction.java
public class Subtraction implements Operation { @Override public int apply(int a, int b) { return a - b; }}
乘法實現Multiplication.java
public class Multiplication implements Operation { @Override public int apply(int a, int b) { return a*b; }}
除法實現Division.java
public class Division implements Operation { @Override public int apply(int a, int b) { return a / b; }}
求余實現Modulo.java
public class Modulo implements Operation { @Override public int apply(int a, int b) { return a % b; }}
工廠類OperatorFactory.java
import java.util.HashMap;import java.util.Map;import java.util.Optional;public class OperatorFactory { static Map<String, Operation> operationMap = new HashMap<>(); static { operationMap.put('add', new Addition()); operationMap.put('divide', new Division()); operationMap.put('multiply', new Multiplication()); operationMap.put('subtract', new Subtraction()); operationMap.put('modulo', new Modulo()); } public static Optional<Operation> getOperation(String operation) { return Optional.ofNullable(operationMap.get(operation)); }}
使用示例
public int calculateUsingFactory(int a, int b, String operator) { Operation targetOperation = OperatorFactory .getOperation(operator) .orElseThrow(() -> new IllegalArgumentException('Invalid Operator')); return targetOperation.apply(a, b);}
3.2 枚舉方式重構
枚舉實現Operator.java
public enum Operator { ADD { @Override public int apply(int a, int b) { return a + b; } }, MULTIPLY { @Override public int apply(int a, int b) { return a * b; } }, SUBTRACT { @Override public int apply(int a, int b) { return a - b; } }, DIVIDE { @Override public int apply(int a, int b) { return a / b; } }, MODULO { @Override public int apply(int a, int b) { return a % b; } }; public abstract int apply(int a, int b);}
封裝Operator到Calculator.java
public int calculate(int a, int b, Operator operator) { return operator.apply(a, b);}
使用示例
@Testpublic void whenCalculateUsingEnumOperator_thenReturnCorrectResult() { Calculator calculator = new Calculator(); int result = calculator.calculate(3, 4, Operator.valueOf('ADD')); assertEquals(7, result);}
3.3 命令模式
抽象的接口
public interface Command { Integer execute();}
實現類
package com.baeldung.reducingIfElse;public class AddCommand implements Command { private int a; private int b; public AddCommand(int a, int b) { this.a = a; this.b = b; } @Override public Integer execute() { return a + b; }}
其它略包裝
public int calculate(Command command) { return command.execute();}
測試demo
@Testpublic void whenCalculateUsingCommand_thenReturnCorrectResult() { Calculator calculator = new Calculator(); int result = calculator.calculate(new AddCommand(3, 7)); assertEquals(10, result);}
3.4 規則引擎重構
抽象規則
public interface Rule { boolean evaluate(Expression expression); Result getResult();}
實現規則AddRule.java 其它略
public class AddRule implements Rule { private int result; @Override public boolean evaluate(Expression expression) { boolean evalResult = false; if (expression.getOperator() == Operator.ADD) { this.result = expression.getX() + expression.getY(); evalResult = true; } return evalResult; } @Override public Result getResult() { return new Result(result); }}
其中:返回結果
public class Result { int value; public Result(int value) { this.value = value; } public int getValue() { return value; }}
表達式
public class Expression { private Integer x; private Integer y; private Operator operator; public Expression(Integer x, Integer y, Operator operator) { this.x = x; this.y = y; this.operator = operator; } public Integer getX() { return x; } public Integer getY() { return y; } public Operator getOperator() { return operator; }}
規則引擎RuleEngine.java
import java.util.ArrayList;import java.util.List;import java.util.Optional;import java.util.stream.Collectors;public class RuleEngine { private static List<Rule> rules = new ArrayList<>(); static { rules.add(new AddRule()); } public Result process(Expression expression) { Rule rule = rules.stream() .filter(r -> r.evaluate(expression)) .findFirst() .orElseThrow(() -> new IllegalArgumentException('Expression does not matches any Rule')); return rule.getResult(); }}
測試demo
@Testpublic void whenNumbersGivenToRuleEngine_thenReturnCorrectResult() { Expression expression = new Expression(5, 5, Operator.ADD); RuleEngine engine = new RuleEngine(); Result result = engine.process(expression); assertNotNull(result); assertEquals(10, result.getValue());}
4.比較
重構方式 SRP OCP DIP LSP LD CARP IF/ELSE N N N N N N 工廠方法 Y Y Y Y Y Y 枚舉方法 N Y Y Y Y Y 命令模式 Y Y Y Y Y Y 規則引擎 Y Y Y Y Y Y
5.小結
為了更好的代碼重用性,可讀性,可靠性,可維護性,我們會嘗試將IF/ELSE或者case-switch進行改造,使用工廠方法,枚舉方法,命令模式,規則引擎方式不同方法進行嘗試,最后使用設計模式的六大原則對代碼進行評估。
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